Question:
There are 200 natural numbers between 1002 and 1012.
Solution:
True
Natural numbers between $100^{2}$ and $101^{2}$
$=10 t^{2}-100^{2}-1 \quad[\because$ natural numbers between $a$ and $b=b-a-1]$
$=(101+100)(101-100)-1=201-1=200$
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