Question:
Tick (✓) the correct answer
$\left(2^{-5} \div 2^{-2}\right)=?$
(a) $\frac{1}{128}$
(b) $\frac{-1}{128}$
(c) $-\frac{1}{8}$
(d) $\frac{1}{8}$
Solution:
(d) $\frac{1}{8}$
$\left(2^{-5} \div 2^{-2}\right)=\left(\frac{1}{2^{5}} \div \frac{1}{2^{2}}\right)=\left(\frac{1}{32} \div \frac{1}{4}\right)=\left(\frac{1}{32} \times 4\right)=\frac{4}{32}=\frac{1}{8}$
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