Question:
Tick (✓) the correct answer
$\left(\frac{8}{-15}+\frac{4}{-3}\right)=?$
(a) $\frac{28}{15}$
(b) $\frac{-28}{15}$
(c) $\frac{-4}{5}$
(d) $\frac{-4}{15}$
Solution:
(b) $\frac{-28}{15}$
$\frac{8}{-15}=\frac{-8}{15}$ and $\frac{4}{-3}=\frac{-4}{3}$
Now, we have:
$\left(\frac{8}{-15}+\frac{4}{-3}\right)=\left(\frac{-8}{15}+\frac{-4}{3}\right)$
LCM of 15 and 3 is $(3 \times 5 \times 1)$, that is, 15
$\frac{-8}{15}+\frac{-4}{3}=\frac{1 \times(-8)+5 \times(-4)}{15}$
$=\frac{(-8)+(-20)}{15}$
$=\frac{-28}{15}$
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