Question:
Tick (✓) the correct answer
$\left(3+\frac{5}{-7}\right)=?$
(a) $\frac{-16}{7}$
(b) $\frac{16}{7}$
(c) $\frac{-26}{7}$
(d) $\frac{-8}{7}$
Solution:
(b) $\frac{16}{7}$
$3=\frac{3}{1}$ and $\frac{5}{-7}=\frac{-5}{7}$
Now, we have:
$\left(3+\frac{5}{-7}\right)=\left(\frac{3}{1}+\frac{-5}{7}\right)$
LCM of 1 and 7 is 7
$\left(\frac{3}{1}+\frac{-5}{7}\right)=\frac{7 \times 3+1 \times(-5)}{7}$
$=\frac{21+(-5)}{7}$
$=\frac{16}{7}$
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