Question:
Tick (✓) the correct answer
$\left[\left\{\left(-\frac{1}{2}\right)^{2}\right\}^{-2}\right]^{-1}=?$
(a) $\frac{1}{16}$
(b) 16
(c) $-\frac{1}{16}$
(d) $-16$
Solution:
(a) $\frac{1}{16}$
$\left[\left\{\left(-\frac{1}{2}\right)^{2}\right\}^{-2}\right]^{-1}$
$=\left[\left\{-\frac{1}{2}\right\}^{-4}\right]^{-1}$
$=\left(-\frac{1}{2}\right)^{(-4 \times-1)}$
$=\left(-\frac{1}{2}\right)^{4}$
$=\frac{1}{16}$
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