Question:
Tick (✓) the correct answer
If $\frac{6 x+1}{3}+1=\frac{x-3}{6}$, then $x=?$
(a) 1
(b) $-1$
(c) 3
(d) $-3$
Solution:
(b) $-1$
$\frac{6 x+1}{3}+1=\frac{x-3}{6}$
$\Rightarrow \frac{6 x+1+3}{3}=\frac{x-3}{6}$
$\Rightarrow 6(6 x+4)=3(x-3)$
$\Rightarrow 36 x+24=3 x-9$
$\Rightarrow 36 x-3 x=-24-9$
$\Rightarrow 33 x=-33$
$\Rightarrow x=\frac{-33}{33}=-1$
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