Two coins are tossed simultaneously. What is the probability of getting at most one head?
Question:

Two coins are tossed simultaneously. What is the probability of getting at most one head?

(a) $\frac{1}{4}$

(b) $\frac{1}{2}$

(C) $\frac{2}{3}$

(d) $\frac{3}{4}$

 

Solution:

(d) $\frac{3}{4}$

Explanation:
When two coins are tossed simultaneously, the possible outcomes are HH, HT, TH and TT.
Total number of possible outcomes = 4

Let E be the event of getting at most one head.

Then, the favourable outcomes are HT, TH and TT.​
Number of favourable outcomes = 3

$\therefore P($ getting at most 1 head $)=\frac{\text { Number of favo u rable outcomes }}{\text { Total number of possible outcomes }}=\frac{3}{4}$

 

 

 

 

 

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