Question:
What number should be added to $\frac{-5}{11}$ so as to get $\frac{26}{33} ?$
Solution:
Let $x$ be added.
$\therefore x+\frac{-5}{11}=\frac{26}{33}$
$\Rightarrow x=\frac{26}{33}-\frac{-5}{11}$
$\Rightarrow x=\frac{26}{33}-\frac{-15}{33}$
$\Rightarrow x=\frac{26-(-15)}{33}$
$\Rightarrow x=\frac{26+15}{33}$
$\Rightarrow x=\frac{41}{33}$