Question:
What number should be added to $\frac{-5}{8}$ so as to get $\frac{-3}{2} ?$
Solution:
Let the required number be x.
Now,
$\frac{-5}{8}+x=\frac{-3}{2}$
$\Rightarrow \frac{-5}{8}+x+\frac{5}{8}=\frac{-3}{2}+\frac{5}{8} \quad$ (Adding $\frac{5}{8}$ to both the sides)
$\Rightarrow x=\left(\frac{-3}{2}+\frac{5}{8}\right)$
$\Rightarrow x=\left(\frac{-12}{8}+\frac{5}{8}\right)$
$\Rightarrow x=\left(\frac{-12+5}{8}\right)$
$\Rightarrow x=\frac{-7}{8}$
Hence, the required number is $\frac{-7}{8}$.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.