Question:
What value of y would make AOB a line in the below figure, If ∠AOB = 4y and ∠BOC = (6y + 30)?
Solution:
Since, ∠AOC and ∠BOC are linear pairs
∠AOC + ∠BOC = 180°
6y + 30 + 4y = 180
10y + 30 = 180
10y = 180 - 30
10y = 150
y = 150/10
y = 15
Hence value of y that will make AOB a line is 15°
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