When 0.1 mol CoCl3(NH3)5 is treated

Question:

When 0.1 mol CoCl3(NH3)5 is treated with an excess of AgNO3, 0.2 mol of AgCl

are obtained. The conductivity of the solution will correspond to

(i) 1:3 electrolyte

(ii) 1:2 electrolyte

(iii) 1:1 electrolyte

(iv) 3:1 electrolyte

Solution:

Option (ii)  1:2 electrolyte  is the answer.

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