Which of the following can not be valid assignment of probabilities for outcomes of sample space
Which of the following can not be valid assignment of probabilities for outcomes of sample space $S=\left\{\omega_{1}, \omega_{2}, \omega_{3}, \omega_{4}, \omega_{5}, \omega_{6}, \omega_{7}\right\}$


Here, each of the numbers p(ωi) is positive and less than 1.
Sum of probabilities
$=p\left(\omega_{1}\right)+p\left(\omega_{2}\right)+p\left(\omega_{3}\right)+p\left(\omega_{4}\right)+p\left(\omega_{5}\right)+p\left(\omega_{6}\right)+p\left(\omega_{7}\right)$
$=0.1+0.01+0.05+0.03+0.01+0.2+0.6$
$=1$
Thus, the assignment is valid.

Here, each of the numbers p(ωi) is positive and less than 1.
Sum of probabilities
$=p\left(\omega_{1}\right)+p\left(\omega_{2}\right)+p\left(\omega_{3}\right)+p\left(\omega_{4}\right)+p\left(\omega_{5}\right)+p\left(\omega_{6}\right)+p\left(\omega_{7}\right)$
$=\frac{1}{7}+\frac{1}{7}+\frac{1}{7}+\frac{1}{7}+\frac{1}{7}+\frac{1}{7}+\frac{1}{7}=7 \times \frac{1}{7}=1$
Thus, the assignment is valid.
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Here, each of the numbers p(ωi) is positive and less than 1.
Sum of probabilities

Here, $p\left(\omega_{1}\right)$ and $p\left(\omega_{5}\right)$ are negative.
Hence, the assignment is not valid.

Here, $p\left(\omega_{7}\right)=\frac{15}{14}>1$
Hence, the assignment is not valid.