Question:
Which of the following order of energies of molecular orbitals of N2 is correct?
(i) (π2py ) < (σ2pz) < (π*2px) ≈ (π*2py)
(ii) (π2py ) > (σ2pz) > (π*2px) ≈ (π*2py )
(iii) (π2py ) < (σ2pz) > (π*2px) ≈ (π*2py )
(iv) (π2py ) > (σ2pz) < (π*2px) ≈ (π*2py )
Solution:
Option (i) is the answer.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.