Write a balanced chemical equation for each of the following reactions and also classify them.
(a) Lead acetate solution is treated with dilute hydrochloric acid to form lead chloride and acetic acid solution.
(b) A piece of sodium metal is added to absolute ethanol to form sodium ethoxide and hydrogen gas.
(c) Iron (III) oxide on heating with carbon monoxide gas reacts to form solid iron and liberates carbon dioxide gas.
(d) Hydrogen sulphide gas reacts with oxygen gas to form solid sulphur and liquid water. (CBSE 2014)
(a) $\mathrm{Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}(s)+2 \mathrm{HCl}(a q) \longrightarrow \mathrm{PbCl}_{2}(s)+\mathrm{CH}_{3} \mathrm{COOH}(a q) ;$ Double displacement reaction
(b) $2 \mathrm{Na}(s)+2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l) \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{ONa}(l)+\mathrm{H}_{2}(g)$;
Displacement reaction
(c) $\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{CO}(g) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{CO}_{2}(g)$;
Redox reaction
(d) $2 \mathrm{H}_{2} \mathrm{~S}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{~S}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)$;
Redox reaction.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.