Question:
Write the number of 5 digit numbers that can be formed using digits 0, 1 and 2.
Solution:
Number of ways in which the first digit can be filled = Number of digits available for filling it = 2 {1,2} (Since the first one cannot be 0)
Number of ways of filling the remaining four palaces = 3 each (as each place can be filled with either 1, 2 or 0)
By fundamental principle of counting, number of five digit numbers that can be formed $=2 \times 3 \times 3 \times 3 \times 3=2 \times 3^{4}$
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