JEE Advanced Previous Year Questions of Chemistry with Solutions are available at eSaral. Practicing JEE Advanced Previous Year Papers Questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas.

*Simulator*

**Previous Years JEE Advanced Questions**

(A) X is a reducing sugar and Y is a non‑reducing sugar

(B) X is a non‑reducing sugar and Y is a reducing sugar

(C) The glucosidic linkages in X and Y are $\alpha$ and $\beta$ , respectively.

(D) The glucosidic linkages in X and Y are $\beta$ and $\alpha$ , respectively.

**[JEE 2009]**

**Sol.**(B,C)

(A) Nylon

(B) Poly (vinyl chloride)

(C) Cellulose

(D) Natural Rubber

**[JEE 2009]**

**Sol.**(D)

Natural rubber is elastomer and has weak vander waal force of attraction and the unit (monomer) is

(A) a ketohexose (B) an aldohexose (C) an $\alpha$-furanose (D) an $\alpha$-pyranose

**[JEE 2011]**

**Sol.**(B)

(A) Ring **(a)** is pyranose with a–glycosidic link

(B) Ring **(a)** is furanose with a–glycosidic link

(C) Ring **(b)** is furanose with a–glycosidic link

(D) Ring **(b)** is pyranose with b–glycosidic link

**[IIT-2010]**

**Sol.**(A)

The ring is pyranose with glycosidic linkage which means the oxide linkage which

connect the monosaccharide units in polysaccharides.

(A) 3 (B) 0 (C) 2 (D) 1

**[IIT-2010]**

**Sol.**(C)

The two basic groups are $\mathrm{NH}_{2}$ and $\mathrm{COO}^{-}$ groups.

(A) a hemiacetal (B) an acetal (C) an ether (D) an ester

**[JEE 2011]**

**Sol.**(B)

**[JEE 2011]**

**Sol.**(C)

(A) $\mathrm{X}=\mathrm{COOCH}_{3}, \mathrm{Y}=\mathrm{H}_{2} / \mathrm{Ni} / \mathrm{heat}$

(B) $\mathrm{X}=\mathrm{CONH}_{2}, \mathrm{Y}=\mathrm{H}_{2} / \mathrm{Ni} / \mathrm{heat}$

(C) $\mathrm{X}=\mathrm{CONH}_{2}, \mathrm{Y}=\mathrm{Br}_{2} / \mathrm{NaOH}$

(D) $\mathrm{X}=\mathrm{CN}, \mathrm{Y}=\mathrm{H}_{2} / \mathrm{Ni} / \mathrm{heat}$

**[JEE 2011]**

**Sol.**(A,B,C,D)

The structure of L(–)-glucose is

**[IIT 2011]**

**Sol.**(A)

The structure of D(+) glucose is

**[JEE 2011]**

**Sol.**6

No. of peptide linkage $=$ No. of water molecules added for complete hydrolysis.

= n – 1

So, number of molecules of $\mathrm{H}_{2} \mathrm{O}$ added $=9$

So total wt. of the product $=$ Mol. wt. of polypeptide $+$ total wt. of $\mathrm{H}_{2} \mathrm{O}$ added.

= 796 + (9 × 16)

= 796 + 162

= 958

$\therefore$ wt. of glycine obtained $=958 \times \frac{47}{100} \square 450$

No. of units of glycine $=\frac{450}{75}=6$ units

**[JEE 2012]**

**Sol.**4

**[JEE 2012]**

**Sol.**8

**[JEE 2013]**

**Sol.**4

Considering alanin at one end of tetra peptides structure with $\mathrm{CO}_{2} \mathrm{H}$ group, number of possible combination are as follows:

(i) $\&$ (ii) can not be the possible because in those combination $-\mathrm{NH}_{2}$ group is not attached to chiral centre.

Hence, answer is (4)

**obtained by complete acidic hydrolysis of the peptide shown below is**

*distinct naturally occurring amino acids*

**[JEE 2014]**

**Sol.**1

**[JEE – Adv. 2016]**

**Sol.**(A,B,C)

Tollens’s test is given by compounds having aldehyde group. Also -hydroxy carbonyl gives positive tollen’s test.

(Given : specific rotations of (+)-sucrose, (+)-maltose, L-(–)-glucose and L-(+)-fructose in aqueous solution are $+66^{\circ},+140^{\circ},-52^{\circ}$ and $+92^{\circ}$, respectively)

(A) ‘invert sugar’ is prepared by acid catalyzed hydrolysis of maltose

(B) ‘invert sugar’ is an equimolar mixture of D-(+) glucose and D-(–)-fructose

(C) specific rotation of ‘invert surgar’ is $-20^{\circ}$

(D) on reaction with $\mathrm{Br}_{2}$ water, ‘invert sugar’ forms saccharic acid as one of the products

**[JEE – Adv. 2016]**

**Sol.**(B,C)

Invert sugar is equailmolar mixture of D-glucose and D-fructose which is obtained by hydrolysis of sucrose

Specific rotation of mixture is half of sum of sp. rotation of both components $\frac{+52^{\circ}+\left(-92^{\circ}\right)}{2}$

$=-20^{\circ}$

**Paragraph (q. 17 TO q. 18)**

Treatment of compound **O** with $\mathrm{KMnO}_{4} / \mathrm{H}^{+}$ gave **P**, which on heating with ammonia gave **Q**. The compound **Q** on treatment with $\mathrm{Br}_{2} / \mathrm{NaOH}$ produced **R**. On strong heating, **Q** gave **S**, which on further treatmenet with ethyl 2-bromopropanoate in the presence of KOH following by acidification, gave a compound **T**.

**R**is :

**[JEE – Adv. 2016] **

**Sol.**(A)

**T**is :

(A) Glycine (B) Alanine (C) Valine (D) Serine

**[JEE – Adv. 2016] **

**Sol.**(B)

The correct structure(s) of $\beta$-glucopyranose is (are) :-

**[JEE Adv. 2018]**

**Sol.**(D)

In last question L is missing in question , correct it