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**Previous Years JEE Advanced Questions**

**[JEE 2010]**

**Sol.**8

$420=\left(m \times 10^{-3}\right)(2100)(5)+\left(1 \times 10^{-3}\right) \times\left(3.36 \times 10^{5}\right)$

$m=8 \mathrm{gm}$

(Specific heat of water is $4.2 \mathrm{kJ} \mathrm{kg}^{-1} \mathrm{K}^{-1}$ and the density of water is $1000 \mathrm{kg} \mathrm{m}^{-3}$ )

(A) 1600

(B) 2067

(C) 2533

(D) 3933

**[JEE-Advance-2016]**

**Sol.**(B)

$3000-\mathrm{P}=(120 \times 1)\left(4.2 \times 10^{3}\right) \frac{\mathrm{dT}}{\mathrm{dt}}$

$\frac{\mathrm{dT}}{\mathrm{dt}}=\frac{20}{60 \times 60 \times 3}$

$\mathrm{P}=2067 \mathrm{W}$

thanks