Differentiability – JEE Main Previous Year Question with Solutions

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Q. Let $\mathrm{f}(\mathrm{x})=\mathrm{x}|\mathrm{x}|$ and $\mathrm{g}(\mathrm{x})=\sin \mathrm{x}$ Statement–1 : gof is differentiable at x = 0 and its derivative is continuous at that point. Statement–2 : gof is twice differentiable at x = 0. (1) Statement–1 is true, Statement–2 is false. (2) Statement–1 is false, Statement–2 is true. (3) Statement–1 is true, Statement–2 is true; Statement–2 is a correct explanation for Statement– 1. (4) Statement–1 is true, Statement–2 is true ; Statement–2 is not a correct explanation for statement– 1. [AIEEE-2009]

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Sol. (1) $F(x)=x|x| \quad g(x)=\sin x$ $\operatorname{gof}=\sin x|x|=\left[\begin{array}{cc}{2 x \cos x^{2}} & {x>0} \\ {-2 x \cos x^{2}} & {x<0}\end{array}\right.$ $(\mathrm{gof})^{\prime \prime}=\left[\begin{array}{cc}{2 \cos \mathrm{x}^{2}-4 \mathrm{x}^{2} \sin \mathrm{x}^{2}} & {\mathrm{x}>0} \\ {-2 \cos \mathrm{x}^{2}+4 \mathrm{x}^{2} \sin \mathrm{x}^{2}} & {\mathrm{x}<0}\end{array}\right.$ $\Rightarrow$ First derivative exist but second derivative doesn’t exist.

Q. If function $\mathrm{f}(\mathrm{x})$ is differentiable at $\mathrm{x}=\mathrm{a}$ then $\lim _{x \rightarrow a} \frac{\mathrm{x}^{2} \mathrm{f}(\mathrm{a})-\mathrm{a}^{2} \mathrm{f}(\mathrm{x})}{\mathrm{x}-\mathrm{a}}$ (1) $2 \mathrm{a} \mathrm{f}(\mathrm{a})+\mathrm{a}^{2} \mathrm{f}^{\prime}(\mathrm{a})$ (2) $-a^{2} f^{\prime}(a)$ (3) af $(a)-a^{2} f^{\prime}(a)$ (4) $2 \mathrm{af}(\mathrm{a})-\mathrm{a}^{2} \mathrm{f}^{\prime}(\mathrm{a})$ [AIEEE-2011]

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Sol. (4)

Q. Consider the function, $f(x)=|x-2|+|x-5|, x \in R .$ Statement–1 : f'(4) = 0. Statement–2 : f is continuous in [2, 5], differentiable in (2, 5) and f(2) = f(5). [AIEEE 2012] (1) Statement–1 is true, Statement–2 is false. (2) Statement–1 is false, Statement–2 is true. (3) Statement–1 is true, Statement–2 is true ; Statement–2 is a correct explanation for Statement1. (4) Statement–1 is true, Statement–2 is true ; Statement–2 is not a correct explanation for Statement1. [AIEEE 2012]

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Sol. (4)

Q. Let $\mathrm{f}(\mathrm{x})=\mathrm{x}|\mathrm{x}|, \mathrm{g}(\mathrm{x})=\sin \mathrm{x}$ and $\mathrm{h}(\mathrm{x})=(\mathrm{gof})(\mathrm{x}) .$ Then (1) h(x) is differentiable at x = 0 (2) h(x) is continuous at x = 0 but is not differentiable at x = 0 (3) h(x) is differentiable at x = 0 but h(x) is not continuous at x = 0 (4) h(x) is not differentiable at x = 0 [On-line 2014]

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Sol. (2)

Q. Let $\mathrm{f}, \mathrm{g}: \mathrm{R} \rightarrow \mathrm{R}$ be two functions defined byf(x) $=\left\{\begin{array}{ll}{\mathrm{x} \sin \left(\frac{1}{\mathrm{x}}\right), \mathrm{x} \neq 0} & {, \text { and } \mathrm{g}(\mathrm{x})=\mathrm{xf}(\mathrm{x}):-} \\ {0} & {, \mathrm{x}=0}\end{array}\right.$ Statement I : f is a continuous function at x = 0. Statement II : g is a differentiable function at x = 0. (1) Statement I is false and statement II is true (2) Statement I is true and statement II is false (3) Both statement I and II are true (4) Both statements I and II are false [on-line 2014]

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Sol. (3)

Q. Let $\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R}$ be a function such that $|\mathrm{f}(\mathrm{x})| \leq \mathrm{x}^{2},$ for all $\mathrm{x} \in \mathrm{R} .$ Then, at $\mathrm{x}=0, \mathrm{f}$ is: (1) Neither continuous nor differentiable (2) differentiable but not continuous (3) continuous as well as differentiable (4) continuous but not differentiable [on-line 2014]

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Sol. (3) $|\mathrm{f}(\mathrm{x})| \leq \mathrm{x}^{2}$ $-\mathrm{x}^{2} \leq \mathrm{f}(\mathrm{x}) \leq \mathrm{x}^{2} \therefore$ at $\mathrm{x}=0 \mathrm{f}(\mathrm{x})$ is continuons as well as differentiable

Q. For $\mathrm{x} \in \mathrm{R}, \mathrm{f}(\mathrm{x})=|\log 2-\sin \mathrm{x}|$ and $\mathrm{g}(\mathrm{x})=\mathrm{f}(\mathrm{f}(\mathrm{x})),$ then : (1) $\mathrm{g}$ is differentiable at $\mathrm{x}=0$ and $\mathrm{g}^{\prime}(0)=-\sin (\log 2)$ (2) $\mathrm{g}$ is not differentiable at $\mathrm{x}=0$ (3) $\mathrm{g}^{\prime}(0)=\cos (\log 2)$ (4) $\mathrm{g}^{\prime}(0)=-\cos (\log 2)$ [JEE Mains 2016]

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Sol. (3)

Q. Let $\mathrm{S}=\left\{\mathrm{t} \in \mathrm{R}: \mathrm{f}(\mathrm{x})=|\mathrm{x}-\pi| \cdot\left(\mathrm{e}^{|\mathrm{x}|}-1\right)\right.$ $\sin |x|$ is not differentiable at t}. Then the set S is equal to: (1) {0}           (2) $\{\pi\}$           (3) $\{0, \pi\}$              (4) $\phi$ (an empty set) [JEE Mains 2018]

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Sol. (4)

Q. Let $\mathrm{S}=\{\lambda, \mu)$ $\varepsilon \operatorname{RxR}: f(t)$ $\left.=(|\lambda|) \mathrm{e}^{|t|}-\mu\right)$. $\sin (2|\mathrm{t}|)$, $\mathrm{t} \varepsilon \mathrm{R},$ is a differentiable function}.Then S is a subset of : (1) $[0, \infty) \times \mathrm{R}$ (2) $\mathrm{R} \times(-\infty, 0)$ (3) $\mathrm{R} \times[0, \infty)$ (4) $(-\infty, 0) \times \mathrm{R}$ [JEE Mains 2018]

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Sol. (3)

• December 4, 2020 at 10:55 pm

happy

6
• December 4, 2020 at 10:55 pm

0
• September 1, 2020 at 10:07 am

🙂… nice

0
• September 1, 2020 at 10:06 am

🙂

0
• August 14, 2020 at 12:08 pm