Elasticity – JEE Advanced Previous Year Questions with Solutions

JEE Advanced Previous Year Questions of Physics with Solutions are available at eSaral. Practicing JEE Advanced Previous Year Papers Questions of Physics will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas.

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Previous Years JEE Advanced Questions

Q. A 0.1 kg mass is suspended from a wire of negligible mass. The length of the wire is 1m and its cross–sectional area is $4.9 \times 10^{-7} \mathrm{m}^{2}$. If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency 140 rad s–1. If the Young’s modulus of the material of the wire is $\mathrm{n} \times 10^{9} \mathrm{Nm}^{-2}$, the value of n is ?

[IIT-JEE 2010]

Sol. 4

$\mathrm{F}=6 \mathrm{A}=\mathrm{YSA}=\frac{\mathrm{YA}}{\ell} \cdot \mathrm{x}$

$140=\sqrt{\frac{\mathrm{n} \times 10^{9} \times 4.9 \times 10^{-7}}{1 \times 0.1}}=70 \times \sqrt{\mathrm{n}}$

$\therefore \mathrm{n}=4$


Q. One end of a horizontal thick copper wire of length 2L and radius 2R is welded to an end of another horizontal thin copper wire of length L and radius R. When the arrangement is stretched by applying forces at two ends, the ratio of the elongation in the thin wire to that in the thick wire is :-

(A) 0.25 (B) 0.50 (C) 2.00 (D) 4.00

[JEE-Advance-2013]

Sol. (C)

Force same = F

$\mathrm{Y}=\frac{F / A}{\Delta L / L}$

$F=Y A_{1} \frac{\Delta L_{1}}{L_{1}}=Y A_{2} \frac{\Delta L_{2}}{L_{2}}$

$\frac{\Delta L_{2}}{\Delta L_{1}}=\frac{L_{2}}{L_{1}} \times \frac{A_{1}}{A_{2}}$


Q. In plotting stress versus strain curves for two materials P and Q, a student by mistake puts strain on the y-axis and stress on the x-axis as shown in the figure. Then the correct statement(s) is (are):-

(A) P has more tensile strength than Q

(B) P is more ductile than Q

(C) P is more brittle than Q

(D) The Young’s modulus of P is more than that of Q

[JEE-Advance-2015]

Sol. (A,B)

Slope of this graph represents the reciprocal of Young’s modulus.

since Slope of P > Slope of Q

Hence Y of P < Y of Q


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