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General Organic Chemistry - JEE Advanced Previous Year Questions with Solutions

General Organic Chemistry JEE Advanced PYQ: Practice previous year JEE Advanced questions on resonance, inductive effect, hyperconjugation, acidity, aromaticity, and reaction mechanisms to build a strong Organic Chemistry foundation.

General Organic Chemistry - JEE Advanced Previous Year Questions with Solutions

Table of Contents

JEEJEE Main ›General Organic Chemistry 

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Why GOC Is Critical for JEE Advanced 

General Organic Chemistry is the foundation of the entire Organic Chemistry section in JEE Advanced. Without a solid grasp of concepts like inductive effects, resonance, hyperconjugation, and aromaticity, students struggle to solve even straightforward reaction-mechanism questions in later chapters.

According to the official NTA/IIT JEE paper analysis, Organic Chemistry as a whole contributes roughly 30–35% of Chemistry marks in JEE Advanced. Within that, GOC — though a single chapter — is the most frequently tested conceptual area because its principles underpin every other organic topic.

JEE Advanced PYQs with Solutions

JEE Advanced Previous Year Questions of Chemistry with Solutions are available at eSaral. Practicing JEE Advanced Previous Year Papers Questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. Simulator   Previous Years JEE Advance Questions

Q. The correct acidity order of the following is : (A) (III) > (IV) > (II) > (I) (B) (IV) > (III) > (I) > (II) (C) (III) > (II) > (I) > (IV) (D) (II) > (III) > (IV) > (I) [IIT-JEE-2009]
Ans. (A) (A) Acidity $\propto-R /-I \propto \frac{1}{+R /+I}$
Q. The correct stability order of the following resonance structures is [IIT-2009]
Ans. (B)
Q. Amongst the following, the total number of compounds soluble in aquesous NaOH is: [IIT-JEE-2010]
Ans. 4 (4) Compound which is more acidic than water is soluble in NaOH
Q. The total number of contributing structures showing hyperconjugation (involving C–H bonds) for the following carbocation is. [IIT-2011]
Ans. 6 $6 \propto \mathrm{H}$ ore present.
Q. Among the following compounds, the most acidic is – (A) p-nitrophenol (B) p-hydroxybenzoic acid (C) o-hydroxybenzoic acid (D) p-toluic acid [IIT-JEE-2011]
Ans. (C)
Q. Which of the following molecules, in pure from , is (are) unstable at room temperature ? [IIT-2012]
Ans. (B,C) Anti - Aromatic : B,C
Q. The carboxyl functional group (–COOH) is present in – (A) picric acid (B) barbituric acid (C) ascorbic acid (D) aspirin [IIT-JEE-2012]
Ans. (D)
Q. Identify the binary mixtures (s) that can be separated into the individual compounds, by differential extraction, as shown in the given scheme - (A) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}$ (B) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}$ (C) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}$ (D) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{COOH}$ [IIT-JEE-2012]
Ans. (B,D)
Q. The hyperconjugative stbilities of tert-butyl cation and 2-butene, respectively, are due to – (A) $\sigma \rightarrow \mathrm{p}$ (empty) and $\sigma \rightarrow \pi$ electron delocalisations (B) $\sigma \rightarrow \sigma$ and $\sigma \rightarrow \pi$ electron delocalisations (C) $\sigma \rightarrow \mathrm{p}(\text { filled })$ and $\sigma \rightarrow \pi$ electron delocalisations (D) $\mathrm{p}$ (filled) $\rightarrow \sigma$ and $\sigma \rightarrow \pi$ electron delocalisations [IIT-2013]
Ans. (A)
Q. The total number of lone-pairs of electrons in melamine is - [IIT-2013]
Ans. 6
Q. The compound that does NOT liberate $\mathrm{CO}_{2}$, on treatment with aqueous sodium bicarbonate solution, is – (A) Benzoic acid (B) Benzenesulphonic acid (C) Salicylic acid (D) Carbolic acid (phenol) [JEE-ADVANCED-2013]
Ans. (D) (D) Compound which is more acidic than $\mathrm{H}_{2} \mathrm{CO}_{3}$ liberate $\mathrm{CO}_{2}$ gas.
Q. Hydrogen bonding plays a central role in the following phenomena (A) Ice floats in water (B) Higher Lewis basicity of primary amines than tertiary amines in aqueous solutions (C) Formic acid is more acidic than acetic acid (D) Dimerisation of acetic acid in benzene [JEE-ADVANCED-2014]
Ans. (A,B,D)
Q. The number of resonance structures for N is : [IIT-2015]
Ans. 9

Frequently Asked Questions

Find answers to common questions.

How many questions from General Organic Chemistry appear in JEE Advanced each year?

GOC typically contributes 2–4 questions per JEE Advanced paper. The exact number varies by year, but the chapter has appeared consistently since 2009. Because each GOC question is often high in marks (3–4 marks), even one well-prepared concept can shift your rank significantly.

Is GOC asked in JEE Main as well as JEE Advanced?

Yes. GOC appears in both JEE Main and JEE Advanced, but JEE Advanced questions are more application-heavy and often test two or three concepts in a single question — for example, combining resonance with acidity order in one MCQ.


What is the fastest way to learn acidity order for JEE Advanced?

Start by memorising the four effect types (inductive, resonance, ortho, field), then practise ranking acids by asking: which effect dominates, and does it stabilise or destabilise the conjugate base? Solving 20–30 ranked acidity problems from previous year papers builds the required intuition quickly.

How do you count hyperconjugative structures for a carbocation?

Count the total number of α-hydrogen atoms — that is, every C–H bond on a carbon directly bonded to the carbocation centre. Each α-hydrogen contributes exactly one hyperconjugative (no-bond resonance) structure. For the tert-butyl cation, there are 9 α-hydrogens and thus 9 hyperconjugative structures

Why is phenol not soluble in NaHCO₃ solution?

Phenol (pKa ≈ 10) is a weaker acid than carbonic acid (pKa₁ ≈ 6.35). A compound can displace CO₂ from NaHCO₃ only if it is a stronger acid than H₂CO₃. Since phenol cannot donate a proton to HCO₃⁻ in a thermodynamically favourable reaction, it does not dissolve in NaHCO₃.


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