JEE Main Previous Year Question of Physics with Solutions are available here. Practicing JEE Main Previous Year Papers Questions of Physics will help all the JEE aspirants in realizing the question pattern as well as help in analyzing their weak & strong areas.

Get detailed Class 11th &12th Physics Notes to prepare for Boards as well as competitive exams like IIT JEE, NEET etc.

eSaral helps the students in clearing and understanding each topic in a better way. eSaral is providing complete chapter-wise notes of Class 11th and 12th both for all subjects.

Besides this, eSaral also offers NCERT Solutions, Previous year questions for JEE Main and Advance, Practice questions, Test Series for JEE Main, JEE Advanced and NEET, Important questions of Physics, Chemistry, Math, and Biology and many more.

Download eSaral app for free study material and video tutorials.

Get detailed Class 11th &12th Physics Notes to prepare for Boards as well as competitive exams like IIT JEE, NEET etc.

eSaral helps the students in clearing and understanding each topic in a better way. eSaral is providing complete chapter-wise notes of Class 11th and 12th both for all subjects.

Besides this, eSaral also offers NCERT Solutions, Previous year questions for JEE Main and Advance, Practice questions, Test Series for JEE Main, JEE Advanced and NEET, Important questions of Physics, Chemistry, Math, and Biology and many more.

Download eSaral app for free study material and video tutorials.

*Simulator***Previous Years AIEEE/JEE Mains Questions**Q. A particle has an initial velocity of $3 \hat{i}+4 \hat{j}$ and an acceleration of $0.4 \hat{\mathrm{i}}+0.3 \hat{\mathrm{j}}$. Its speed after 10s is :-
(1) 7 units
(2) 8.5 units
(3) 10 units
(4) $7 \sqrt{2}$ units

**[AIEEE-2009]**Ans. (4)
v = u + at
u = 3i + 4j + (0.4 i + 0.3 j) × 10
= 3i + 4j + 4i + 3i
u = 7i + 7j
$|\overrightarrow{\mathrm{u}}|=\sqrt{7^{2}+7^{2}}$
$=7 \sqrt{2}$

Q. An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by $\frac{\mathrm{dv}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$ where v is the instantaneous speed. The time taken by the object, to come to rest, would be :-
(1) 4 s (2) 8 s (3) 1 s (4) 2 s

**[AIEEE-2011]**Ans. (4)
$\overrightarrow{\mathrm{a}}=\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}$
$\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$
$\int \mathrm{d} \mathrm{v} \times \mathrm{v}^{-1 / 2}=\int-2.5 \mathrm{dt}$
$\frac{\mathrm{v}^{\frac{1}{2}}}{\frac{1}{2}}=-2.5 \mathrm{t}$
$2 \sqrt{\mathrm{v}}=-2.5 \mathrm{t}+\mathrm{c}$
$2 \sqrt{6.25}=-2.5 \mathrm{t}+\mathrm{c}$
2 × 0.25 = c
5 = c
$2 \sqrt{\mathrm{v}}=-\mathrm{kt}+5$
0 = –kt + 5
kt = 5
$\mathrm{t}=\frac{5 \mathrm{sec}}{2.5}=2 \mathrm{sec}$

Q. From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is :
(1) $2 \mathrm{g} \mathrm{H}=\mathrm{nu}^{2}(\mathrm{n}-2)$
(2) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2) \mathrm{u}^{2}$
(3) $2 \mathrm{g} \mathrm{H}=\mathrm{n}^{2} \mathrm{u}^{2}$
(4) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2)^{2} \mathrm{u}^{2}$

**[JEE-MAIN-2014]**Ans. (1)
Time to reach highest point $=\mathrm{t}=\frac{\mathrm{u}}{\mathrm{g}}$
time to reach ground = nt
$\mathrm{S}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}$
$-\mathrm{H}=\mathrm{u}(\mathrm{nt})-\frac{1}{2} \mathrm{g}(\mathrm{nt})^{2}$
$\Rightarrow 2 \mathrm{gH}=\mathrm{nu}^{2}(\mathrm{n}-2)$

Q. A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time ?

**[JEE Mains - 2017]**Ans. (1)
Velocity at any time t is
given by
v = u + at
v = v0 + (–g)t
$\mathrm{v}=\mathrm{v}_{0}-\mathrm{gt}$
$\Rightarrow$ straight line with negative slope

Q. All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.

**[JEE Mains - 2018]**Ans. (1)
In this question option (2) and (4) are the corresponding position - time graph and velocity –position graph of option (3) and its distance – time graph is given as
Hence incorrect graph is option (1)

## Comments

on line pharmacy

Oct. 18, 2023, 7:03 a.m.

I go to see each day a few sites and information sites to read articles, except this blog presents quality based content.

potty

May 15, 2021, 11:33 p.m.

PLS ADD MORE QUESTIONS , ELSE PLS DIE
You miss 100% of the shots you don't take." - ...
"Whether you think you can or you think you can't, you're right." - ...
"I have learned over the years that when one's mind is made up, this diminishes fear." - ...
"I alone cannot change the world, but I can cast a stone across the water to create many ripples." -

mr.random

April 21, 2021, 8:54 a.m.

yes we all know u are fucking ur parents hard earned money and later ur future is going to fuck u

Harshit Sharma

Feb. 17, 2021, 2:20 p.m.

these are not enough for practise but uploads some more questions
i really need of more privious questions

JEEBAN KUMAR BARIK.🥰

Oct. 10, 2020, 6:47 a.m.

Well/but not hard is pick up/plz update harder omes🙏🙏🙏🙏