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eSaral helps the students in clearing and understanding each topic in a better way. eSaral is providing complete chapter-wise notes of Class 11th and 12th both for all subjects.

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*Simulator***Previous Years AIEEE/JEE Mains Questions**Q. A particle has an initial velocity of $3 \hat{i}+4 \hat{j}$ and an acceleration of $0.4 \hat{\mathrm{i}}+0.3 \hat{\mathrm{j}}$. Its speed after 10s is :-
(1) 7 units
(2) 8.5 units
(3) 10 units
(4) $7 \sqrt{2}$ units

**[AIEEE-2009]**Ans. (4)
v = u + at
u = 3i + 4j + (0.4 i + 0.3 j) × 10
= 3i + 4j + 4i + 3i
u = 7i + 7j
$|\overrightarrow{\mathrm{u}}|=\sqrt{7^{2}+7^{2}}$
$=7 \sqrt{2}$

Q. An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by $\frac{\mathrm{dv}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$ where v is the instantaneous speed. The time taken by the object, to come to rest, would be :-
(1) 4 s (2) 8 s (3) 1 s (4) 2 s

**[AIEEE-2011]**Ans. (4)
$\overrightarrow{\mathrm{a}}=\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}$
$\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$
$\int \mathrm{d} \mathrm{v} \times \mathrm{v}^{-1 / 2}=\int-2.5 \mathrm{dt}$
$\frac{\mathrm{v}^{\frac{1}{2}}}{\frac{1}{2}}=-2.5 \mathrm{t}$
$2 \sqrt{\mathrm{v}}=-2.5 \mathrm{t}+\mathrm{c}$
$2 \sqrt{6.25}=-2.5 \mathrm{t}+\mathrm{c}$
2 × 0.25 = c
5 = c
$2 \sqrt{\mathrm{v}}=-\mathrm{kt}+5$
0 = –kt + 5
kt = 5
$\mathrm{t}=\frac{5 \mathrm{sec}}{2.5}=2 \mathrm{sec}$

Q. From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is :
(1) $2 \mathrm{g} \mathrm{H}=\mathrm{nu}^{2}(\mathrm{n}-2)$
(2) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2) \mathrm{u}^{2}$
(3) $2 \mathrm{g} \mathrm{H}=\mathrm{n}^{2} \mathrm{u}^{2}$
(4) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2)^{2} \mathrm{u}^{2}$

**[JEE-MAIN-2014]**Ans. (1)
Time to reach highest point $=\mathrm{t}=\frac{\mathrm{u}}{\mathrm{g}}$
time to reach ground = nt
$\mathrm{S}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}$
$-\mathrm{H}=\mathrm{u}(\mathrm{nt})-\frac{1}{2} \mathrm{g}(\mathrm{nt})^{2}$
$\Rightarrow 2 \mathrm{gH}=\mathrm{nu}^{2}(\mathrm{n}-2)$

Q. A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time ?

**[JEE Mains - 2017]**Ans. (1)
Velocity at any time t is
given by
v = u + at
v = v0 + (–g)t
$\mathrm{v}=\mathrm{v}_{0}-\mathrm{gt}$
$\Rightarrow$ straight line with negative slope

Q. All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.

**[JEE Mains - 2018]**Ans. (1)
In this question option (2) and (4) are the corresponding position - time graph and velocity –position graph of option (3) and its distance – time graph is given as
Hence incorrect graph is option (1)

## Comments

balaji

Jan. 28, 2024, 6:35 a.m.

hello sir
i want chapter wise physics subject jee- mains questions with solutions for all previous question papers 2013 to 2023
thank you

on line pharmacy

Oct. 18, 2023, 7:03 a.m.

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potty

May 15, 2021, 11:33 p.m.

PLS ADD MORE QUESTIONS , ELSE PLS DIE
You miss 100% of the shots you don't take." - ...
"Whether you think you can or you think you can't, you're right." - ...
"I have learned over the years that when one's mind is made up, this diminishes fear." - ...
"I alone cannot change the world, but I can cast a stone across the water to create many ripples." -

mr.random

April 21, 2021, 8:54 a.m.

yes we all know u are fucking ur parents hard earned money and later ur future is going to fuck u

Harshit Sharma

Feb. 17, 2021, 2:20 p.m.

these are not enough for practise but uploads some more questions
i really need of more privious questions

JEEBAN KUMAR BARIK.🥰

Oct. 10, 2020, 6:47 a.m.

Well/but not hard is pick up/plz update harder omes🙏🙏🙏🙏

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