*Simulator***Previous Years AIEEE/JEE Mains Questions**

Q. A particle has an initial velocity of $3 \hat{i}+4 \hat{j}$ and an acceleration of $0.4 \hat{\mathrm{i}}+0.3 \hat{\mathrm{j}}$. Its speed after 10s is :-
(1) 7 units
(2) 8.5 units
(3) 10 units
(4) $7 \sqrt{2}$ units

**[AIEEE-2009]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(4) v = u + at u = 3i + 4j + (0.4 i + 0.3 j) × 10 = 3i + 4j + 4i + 3i u = 7i + 7j $|\overrightarrow{\mathrm{u}}|=\sqrt{7^{2}+7^{2}}$ $=7 \sqrt{2}$

Q. An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by $\frac{\mathrm{dv}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$ where v is the instantaneous speed. The time taken by the object, to come to rest, would be :-
(1) 4 s (2) 8 s (3) 1 s (4) 2 s

**[AIEEE-2011]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(4) $\overrightarrow{\mathrm{a}}=\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}$ $\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$ $\int \mathrm{d} \mathrm{v} \times \mathrm{v}^{-1 / 2}=\int-2.5 \mathrm{dt}$ $\frac{\mathrm{v}^{\frac{1}{2}}}{\frac{1}{2}}=-2.5 \mathrm{t}$ $2 \sqrt{\mathrm{v}}=-2.5 \mathrm{t}+\mathrm{c}$ $2 \sqrt{6.25}=-2.5 \mathrm{t}+\mathrm{c}$ 2 × 0.25 = c 5 = c $2 \sqrt{\mathrm{v}}=-\mathrm{kt}+5$ 0 = –kt + 5 kt = 5 $\mathrm{t}=\frac{5 \mathrm{sec}}{2.5}=2 \mathrm{sec}$

Q. From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is :
(1) $2 \mathrm{g} \mathrm{H}=\mathrm{nu}^{2}(\mathrm{n}-2)$
(2) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2) \mathrm{u}^{2}$
(3) $2 \mathrm{g} \mathrm{H}=\mathrm{n}^{2} \mathrm{u}^{2}$
(4) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2)^{2} \mathrm{u}^{2}$

**[JEE-MAIN-2014]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(1) Time to reach highest point $=\mathrm{t}=\frac{\mathrm{u}}{\mathrm{g}}$ time to reach ground = nt $\mathrm{S}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}$ $-\mathrm{H}=\mathrm{u}(\mathrm{nt})-\frac{1}{2} \mathrm{g}(\mathrm{nt})^{2}$ $\Rightarrow 2 \mathrm{gH}=\mathrm{nu}^{2}(\mathrm{n}-2)$

Q. A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time ?

**[JEE Mains – 2017]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(1) Velocity at any time t is given by v = u + at v = v0 + (–g)t $\mathrm{v}=\mathrm{v}_{0}-\mathrm{gt}$ $\Rightarrow$ straight line with negative slope

Q. All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.

**[JEE Mains – 2018]****Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...**

**Sol.**(1) In this question option (2) and (4) are the corresponding position – time graph and velocity –position graph of option (3) and its distance – time graph is given as Hence incorrect graph is option (1)

PLS ADD MORE QUESTIONS , ELSE PLS DIE

You miss 100% of the shots you don’t take.” – …

“Whether you think you can or you think you can’t, you’re right.” – …

“I have learned over the years that when one’s mind is made up, this diminishes fear.” – …

“I alone cannot change the world, but I can cast a stone across the water to create many ripples.” –

yes we all know u are fucking ur parents hard earned money and later ur future is going to fuck u

Fuck you bro

Nice

fuck exams

these are not enough for practise but uploads some more questions

i really need of more privious questions

Chutiyapa going on

Yes

Very good but would have been better if updated

Well, even the website’s name is ‘e-Saral’. Way too easy.

more and harder questions please but good

Yes, indeed. These questions are way too easy! A better set of questions would do the trick.

Well/but not hard is pick up/plz update harder omes🙏🙏🙏🙏

Yes

How can। idownload it

Please update this

I want more previous year questions for jee mains

Sir pls launch crash course for jee 2021

😘😘

I want more queries

Ya strength of questions are less but helpfull

Thanks esaral these questions are helpful for us

binod

Italy kam questions key bhai .today jadavpur dhudke lao

good questions

tthnk you but just 5 questions!!!!

too less questions

couldn’t understand last one alone

Nice but less questions

Yah you are right

Nice

Good but questions are less

Very helpful but not much helpful…

For practice

fine but very less questions

Xe

good questions could u provide PDF of it

fuckingly less questions

so less questions

Very less questions

Thank you for providing such a good questions

Please can you make a pdf of it.

great effort

Best

Yes

SUPER

hello I am preparing for jee pls help me in physics work power and energy

too few questions

Very helpful. Thank you!!

Plz give more questions.

Can’t u give more questions?

Good job

Plz give more questions..

sir we want to download direct pdf please provide

I want to download questions in PDF how to download

Good question

In This there are less Qestions

Nice