Kinematics 1D- JEE Main Previous Year Questions with Solutions

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Q. A particle has an initial velocity of $3 \hat{i}+4 \hat{j}$ and an acceleration of $0.4 \hat{\mathrm{i}}+0.3 \hat{\mathrm{j}}$. Its speed after 10s is :- (1) 7 units (2) 8.5 units (3) 10 units (4) $7 \sqrt{2}$ units [AIEEE-2009]

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Sol. (4) v = u + at u = 3i + 4j + (0.4 i + 0.3 j) × 10 = 3i + 4j + 4i + 3i u = 7i + 7j $|\overrightarrow{\mathrm{u}}|=\sqrt{7^{2}+7^{2}}$ $=7 \sqrt{2}$

Q. An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by $\frac{\mathrm{dv}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$ where v is the instantaneous speed. The time taken by the object, to come to rest, would be :- (1) 4 s (2) 8 s (3) 1 s (4) 2 s [AIEEE-2011]

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Sol. (4) $\overrightarrow{\mathrm{a}}=\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}$ $\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}=-2.5 \sqrt{\mathrm{v}}$ $\int \mathrm{d} \mathrm{v} \times \mathrm{v}^{-1 / 2}=\int-2.5 \mathrm{dt}$ $\frac{\mathrm{v}^{\frac{1}{2}}}{\frac{1}{2}}=-2.5 \mathrm{t}$ $2 \sqrt{\mathrm{v}}=-2.5 \mathrm{t}+\mathrm{c}$ $2 \sqrt{6.25}=-2.5 \mathrm{t}+\mathrm{c}$ 2 × 0.25 = c 5 = c $2 \sqrt{\mathrm{v}}=-\mathrm{kt}+5$ 0 = –kt + 5 kt = 5 $\mathrm{t}=\frac{5 \mathrm{sec}}{2.5}=2 \mathrm{sec}$

Q. From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is : (1) $2 \mathrm{g} \mathrm{H}=\mathrm{nu}^{2}(\mathrm{n}-2)$ (2) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2) \mathrm{u}^{2}$ (3) $2 \mathrm{g} \mathrm{H}=\mathrm{n}^{2} \mathrm{u}^{2}$ (4) $\mathrm{g} \mathrm{H}=(\mathrm{n}-2)^{2} \mathrm{u}^{2}$ [JEE-MAIN-2014]

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Sol. (1) Time to reach highest point $=\mathrm{t}=\frac{\mathrm{u}}{\mathrm{g}}$ time to reach ground = nt $\mathrm{S}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}$ $-\mathrm{H}=\mathrm{u}(\mathrm{nt})-\frac{1}{2} \mathrm{g}(\mathrm{nt})^{2}$ $\Rightarrow 2 \mathrm{gH}=\mathrm{nu}^{2}(\mathrm{n}-2)$

Q. A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time ? [JEE Mains – 2017]

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Sol. (1) Velocity at any time t is given by v = u + at v = v0 + (–g)t $\mathrm{v}=\mathrm{v}_{0}-\mathrm{gt}$ $\Rightarrow$ straight line with negative slope

Q. All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up. [JEE Mains – 2018]

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Sol. (1) In this question option (2) and (4) are the corresponding position – time graph and velocity –position graph of option (3) and its distance – time graph is given as Hence incorrect graph is option (1)

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Comments
  • March 2, 2021 at 7:24 pm

    fuck exams

    1
  • February 17, 2021 at 2:20 pm

    these are not enough for practise but uploads some more questions
    i really need of more privious questions

    1
  • December 2, 2020 at 10:03 am

    Yes

    2
  • November 28, 2020 at 6:09 pm

    Very good but would have been better if updated

    0
  • November 2, 2020 at 10:18 pm

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    1
  • October 18, 2020 at 4:17 pm

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    2
    • November 2, 2020 at 10:17 pm

      Yes, indeed. These questions are way too easy! A better set of questions would do the trick.

      1
  • October 10, 2020 at 6:47 am

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    0
    • December 2, 2020 at 10:03 am

      Yes

      0
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    0
  • September 27, 2020 at 11:06 pm

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    1
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    0
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  • August 30, 2020 at 12:07 am

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    0
  • August 30, 2020 at 12:06 am

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    0
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  • August 22, 2020 at 11:49 am

    good questions

    0
  • jay
    August 16, 2020 at 11:30 am

    tthnk you but just 5 questions!!!!

    0
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    0
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    0
  • August 7, 2020 at 9:50 am

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    0
    • October 15, 2020 at 10:31 am

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      0
  • August 2, 2020 at 4:08 pm

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  • August 2, 2020 at 1:49 pm

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    0
  • July 26, 2020 at 10:26 pm

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    For practice

    0
  • July 26, 2020 at 2:56 pm

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  • July 14, 2020 at 8:26 am

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    0
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    0
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    0
  • July 4, 2020 at 8:49 pm

    Very less questions

    0
  • July 2, 2020 at 9:50 pm

    Thank you for providing such a good questions
    Please can you make a pdf of it.

    1
  • June 30, 2020 at 1:09 am

    great effort

    0
  • June 22, 2020 at 3:14 pm

    Best

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  • June 18, 2020 at 1:40 pm

    SUPER

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      0
  • June 16, 2020 at 10:30 am

    too few questions

    0
  • June 14, 2020 at 12:43 pm

    Very helpful. Thank you!!

    1
  • May 27, 2020 at 10:10 am

    Plz give more questions.

    0
  • May 27, 2020 at 8:23 am

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    0
  • May 24, 2020 at 4:48 pm

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    1
  • May 20, 2020 at 8:40 pm

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    0
  • May 1, 2020 at 11:09 pm

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    0
  • April 14, 2020 at 2:45 pm

    I want to download questions in PDF how to download

    0
  • April 8, 2020 at 11:36 am

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    0
  • March 29, 2020 at 3:34 pm

    In This there are less Qestions

    0
  • December 19, 2019 at 11:15 pm

    Nice

    0