NCERT Solutions For Class 10 Maths Chapter 8 Exercise 8.3 Introduction To Trigonometry - PDF Download
Class 10NCERT solutions for class 10 maths chapter 8 ex 8.3 Introduction to Trigonometry focuses on one of the most significant sections of this chapter concerning trigonometric identities. This exercise carries maximum weightage in the board exam and also provides easy methods to solve questions. An equation involving trigonometric ratios of an angle is called a trigonometric identity, if it is true for all values of the angle(s) involved.
NCERT solutions class 10 ex 8.3 consists of 4 questions, divided into subparts. The sub-questions are based on the concepts of proving identities using acquired identities. In order to solve the NCERT solutions in class 10 ex 8.3 students need to recall all the concepts from the previous 2 exercises. It is interesting to note that if any of the ratios are known, then we can also find the values of the other trigonometric ratios.
eSaral's NCERT solutions PDF for class 10 maths ex 8.3, designed by subject matter experts, provide an in-depth explanation of each question covered by the ex 8.3. Students can download these free PDFs from eSaral.
Topics Covered in Exercise 8.3 Class 10 Mathematics Questions
NCERT solutions class 10 maths ex 8.3 deals with trigonometric identities.
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Trigonometric Identities |
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Trigonometric Identities - A trigonometric identity is an equation that includes the trigonometric functions sine, cosine, tangent, etc. and is true for all the value of angles θ.
Here, the reference angle is θ, which is taken for a right-angled triangle. You will learn 3 Trigonometric Identities in class 10 ex 8.3.
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cos2 θ + sin2 θ = 1
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1 + tan2 θ = sec2 θ
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cot2 θ + 1 = cosec2 θ
Tips for Solving Exercise 8.3 Class 10 chapter 8 Introduction to Trigonometry
Here are a few tips from our academic team of maths on the topic of trigonometric identities to help you find answers to the questions you may have about ex-8.3.
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NCERT solutions class 10 maths chapter 8 ex 8.3 is based on the proof of the trigonometric identities of questions. Since there are many such questions, the students need to understand the formulas, their derivatives, and their origins. Therefore, it is essential for students to study the proof of all the identities with proper focus.
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NCERT solutions class 10 maths chapter 8 ex 8.3 focuses on understanding concepts. There are some tricky sums that some students might struggle with, but it's all about figuring out what the key point is that can help you get the answer.
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Students can use the formula and value chart they used in the previous exercises to help them understand the question better.
Importance of Solving Ex 8.3 Class 10 Maths chapter 8 Introduction to Trigonometry
Students can explore the advantages of solving ex 8.3 of chapter 8 for class 10 maths.
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The answers to all the questions in ex 8.3 are explained in detail with the help of supporting equations and theories. With the solution provided by eSaral, you can easily learn all the concepts in a short time.
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The PDF version of the solution is available here which can be downloaded from eSaral’s official website.
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The solutions are formulated on the basis of the CBSE syllabus, therefore, following the solution will definitely get you good marks in your maths exam.
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The questions range from simple to difficult so that students can practice all kinds of questions and develop their mindset. The prepared set of questions are more likely to be used in the exam. This will give students a general idea of exam questions.
Frequently Asked Questions
Question 1. How would you define trigonometric identities?
Answer 1. An equation is called an identity when it is true for all values of the variables involved. Similarly, an equation involving trigonometric ratios of an angle is called a trigonometric identity, if it is true for all values of the angles involved.
Question 2. What are the trigonometric identities in ex 8.3 class 10 maths?
Answer 2. There are three trigonometric identities in chapter 8 ex 8.3.
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cos2 θ + sin2 θ = 1
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1 + tan2 θ = sec2 θ
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cot2 θ + 1 = cosec2 θ
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