0.3780 g of an organic chloro compound gave 0.5740 g of silver chloride in Carius estimation.

Given that,

Mass of organic compound is 0.3780 g.

Mass of AgCl formed = 0.5740 g

1 mol of AgCl contains 1 mol of Cl.

Thus, mass of chlorine in 0.5740 g of AgCl

$=\frac{35.5 \times 0.5740}{143.32}$

$=0.1421 \mathrm{~g}$

$\therefore$ Percentage of chlorine $=\frac{0.1421}{0.3780} \times 100=37.59 \%$

Hence, the percentage of chlorine present in the given organic chloro compound is $37.59 \%$.