Question:
$0.3780 \mathrm{~g}$ of an organic chloro compound gave $0.5740 \mathrm{~g}$ of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound.
Solution:
Given that,
Mass of organic compound is 0.3780 g.
Mass of AgCl formed = 0.5740 g
1 mol of AgCl contains 1 mol of Cl.
Thus, mass of chlorine in 0.5740 g of AgCl
$=\frac{35.5 \times 0.5740}{143.32}$
$=0.1421 \mathrm{~g}$
$\therefore$ Percentage of chlorine $=\frac{0.1421}{0.3780} \times 100=37.59 \%$
Hence, the percentage of chlorine present in the given organic chloro compound is $37.59 \%$.
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