100 surnames were randomly picked up from a local telephone directory and frequency distribution of the number of letters in the English alphabet in the surnames was found as follows:
(i) Draw a histogram to depict the given information.
(ii) Write the class interval in which the maximum number of surnames lie.
(i) Here the class intervals are of unequal size. So, we calculate the adjusted frequency using the formula,
Adjusted freq $=\frac{\min \text { class size }}{\text { class size of this class }} \times$ freq
Class sizes are
$4-1=3$
$6-4=2$
$8-6=2$
$12-8=4$
$20-12=8$
Minimum class size = 2
(ii) Maximum number of surnames lie in the interval 6-8.
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