 # 12 defective pens are accidentally mixed up the 132 good ones.

Question:

12 defective pens are accidentally mixed up the 132 good ones. It is not possible to just look at a pen and tell whether it is defective or not. One pen is taken out at random from the lot. Find the probability that the pen taken out is ]

(i) a good one,

(ii) defective

Solution:

Number of defective pens in the lot = 12

Number of good pens in the lot = 132

Total number of pens in the lot = 12 + 132 = 144

∴ Total number of outcomes = 144

(i) There are 132 good pens in the lot. Out of these pens, one good pen can be taken out in 132 ways.

Favourable number of outcomes = 132

$\therefore P(P e n$ taken out is good one $)=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{132}{144}=\frac{11}{12}$

(ii) There are 12 defective pens in the lot. Out of these pens, one defective pen can be taken out in 12 ways.

Favourable number of outcomes = 12

$\therefore P(P$ en taken out is defective $)=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{12}{144}=\frac{1}{12}$