25g of an unkown hydrocarban upon burning produces

eSaral Updated on:
Question:

$25 \mathrm{~g}$ of an unknown hydrocarbon upon burning produces $88 \mathrm{~g}$ of $\mathrm{CO}_{2}$ and $9 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{O}$. This unknown hydrocarbon contains.

  1. $20 \mathrm{~g}$ of carbon and $5 \mathrm{~g}$ of hydrogen

  2. $24 \mathrm{~g}$ of carbon and $1 \mathrm{~g}$ of hydrogen

  3. $18 \mathrm{~g}$ of carbon and $7 \mathrm{~g}$ of hydrogen

  4. $22 \mathrm{~g}$ of carbon and $3 \mathrm{~g}$ of hydrogen

Correct Option: , 2

Solution:

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