A 750 Hz}, 20V rms source is connected to a resistance of 100


A $750 \mathrm{~Hz}, 20 \mathrm{~V}$ (rms) source is connected to a resistance of $100 \Omega$, an inductance of $0.1803 \mathrm{H}$ and a capacitance of $10 \mu \mathrm{F}$ all in series. The time in which the resistance (heat capacity $2 \mathrm{~J} /{ }^{\circ} \mathrm{C}$ ) will get heated by $10^{\circ} \mathrm{C}$. (assume no loss of heat to the surroundings) is close to :

  1. (1) $418 \mathrm{~s}$

  2. (2) $245 \mathrm{~s}$

  3. (3) $365 \mathrm{~s}$

  4. (4) $348 \mathrm{~s}$

Correct Option: , 4



Here, $R=100, X_{L}=L \omega=0.1803 \times 750 \times 2 \pi=850 \Omega$,

$X_{C}=\frac{1}{C \omega}=\frac{1}{10^{-5} \times 2 \pi \times 750}=21.23 \Omega$

Impedance $Z=\sqrt{R^{2}+\left(X_{L}-X_{C}\right)^{2}}$

$=\sqrt{100^{2}+(850-21.23)^{2}}=834.77 \simeq 835$

$H=i_{\mathrm{rms}}^{2} R t=\left(\frac{V_{\mathrm{rms}}}{|Z|}\right)^{2} R T=(m s) \Delta t$

$\Rightarrow \frac{20}{835} \times \frac{20}{835} \times 100 t=(2) \times 10$

$\because V_{\text {rms }}=20 \mathrm{~V}$ and $\Delta \mathrm{t}=10^{\circ} \mathrm{C}$

$\therefore$ Time, $t=348.61 \mathrm{~s}$

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