A bag contains 3 red balls and 5 black balls.

Question:

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is:

(i) red

(ii) black

Solution:

Number of red balls $=3$

Number of black balls $=5$

Total number of balls $=3+5=8$

(i) Let $A$ be the event of drawing a red ball.

$\therefore P(A)=\frac{\text { Number of favourable outcomes }}{\text { Total number of outcomes }}=\frac{3}{8}$

(ii) Let $\mathrm{B}$ be the event of drawing a black ball.

$\therefore P(B)=\frac{\text { Number of favourable outcomes }}{\text { Total number of outcomes }}=\frac{5}{8}$

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