A bag contains 6 red, 8 black and 4 white balls.

Question:

A bag contains 6 red, 8 black and 4 white balls. A ball is drawn at random. What is the probability that ball drawn is not black?

Solution:

Number of red balls $=6$

Number of black balls $=8$

Number of white balls $=4$

Total number of balls $=6+8+4=18$

$\therefore$ Total number of cases $=18$

Again, number of balls that are not black $=18-8=10$

Thus, the number of favourable cases is 10 .

$\therefore P($ the drawn ball is not black $)=\frac{\text { Number of favourable cases }}{\text { Total number cases }}=\frac{10}{18}=\frac{5}{9}$

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