A bag contains slips numbered from 1 to 100 . If Fatima chooses a slip at random from the bag, it will either be an odd number or an even number.
Since, this situation has only two possible outcomes, so the 1 probability of each is $\frac{1}{2}$. Justify.
We know that, between 1 to 100 half numbers are even and half numbers are odd i.e., 50 numbers (2, 4, 6, 8…. 96, 98,100) are even and 50
numbers (1,3, 5, 7. . , 97, 99) are odd.
So, both events are equally likely.
So, probability of getting even number $=\frac{50}{100}=\frac{1}{2}$
and probability of getting odd number $=\frac{50}{100}=\frac{1}{2}$
Hence, the probability of each is $\frac{1}{2}$.
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