Question:
A box contains 3 blue, 2 white and 4 red marbles. If a marbles. If a marble is drawn at random from the box, what is the probability that it will not be a white marble?
(a) $\frac{1}{3}$
(b) $\frac{4}{9}$
(C) $\frac{7}{9}$
(d) $\frac{2}{9}$
Solution:
(C) $\frac{7}{9}$
Explanation:
Total possible outcomes = Total number of marbles
= ( 3 + 2 + 4) = 9
Let E be the event of not getting a white marble.
It means the marble can be either blue or red but not white.
Number of favourable outcomes = (3 + 4) = 7 marbles
$\therefore P($ not getting a white marble $)=\frac{7}{9}$
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