Question:
A card is drawn at random from a well-shuffled pack of 52 cards. What is the probability that the card bears a number greater than 3 and less than 10?
Solution:
We know that,
Probability of occurrence of an event
$=\frac{\text { Total no. of Desired outcomes }}{\text { Total no.of outcomes }}$
Total no. of outcomes are 52
Desired output is a number greater than 3 and less than 10 .
There will be four sets of each card naming $A, 1,2,3,4,5,6,7,8,9,10, J, Q, K .$ So, there will be a total of 24 cards between 3 and 10
Therefore, the probability of picking card between 3 and $10=\frac{24}{52}$
$=\frac{6}{13}$
Conclusion: Probability of picking a card between 3 and 10 is $\frac{6}{13}$