**Question:**

A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, find the area of canvas needed to make the tent.

**Solution:**

Radius of the cylinder = 52.5 m

Radius of the base of the cone = 52.5 m

Slant height (*l*) of the cone = 53 m

Height of the cylinder (*h*) = 3 m

Curved surface area of the cylindrical portion $=2 \pi r h=\left(2 \times \frac{22}{7} \times 52.5 \times 3\right) \mathrm{m}^{2}=990 \mathrm{~m}^{2}$

Curved surface area of the conical portion $=\pi r l=\left(\frac{22}{7} \times 52.5 \times 53\right) \mathrm{m}^{2}=8745 \mathrm{~m}^{2}$

Thus, the total area of canvas required for making the tent $=(8745+990) \mathrm{m}^{2}=9735 \mathrm{~m}^{2}$