Question:
A coin is tossed 60 times and the tail appears 35 times. What is the probability of getting a head?
(a) $\frac{7}{12}$
(b) $\frac{12}{7}$
(c) $\frac{5}{12}$
(d) $\frac{1}{25}$
Solution:
(C) $\frac{5}{12}$
Explanation:
Total number of trials = 60
Number of times tail appears = 35
Number of times head appears = 60 − 35 = 25
Let E be the event of getting a head.
$\therefore P($ getting a head $)=P(E)=\frac{\text { Number of times head appears }}{\text { Total number of trials }}=\frac{25}{60}=\frac{5}{12}$
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