A conical tent is 10 m high and the radius of it base is 24 m.

Solution:

It is given that

Height of the conical tent (h) = 10 m

Radius of conical tent (r) = 24 m

Let slant height of conical tent be l

$\mathrm{I}^{2}=\mathrm{h}^{2}+\mathrm{r}^{2}$

$=10^{2}+24^{2}=100+576$

$=676 \mathrm{~m}^{2}$

⟹ l = 26 m

Thus, the slant height of the conical tent is 26 m.

(ii) It is given that:

Radius(r) = 24 m

Slant height (l) = 26 m

C.S.A of tent = πrl

= 22/7 ∗ 24 ∗ 26

$=1378 / 7 \mathrm{~m}^{2}$

Cost of $1 \mathrm{~m}^{2}$ canvas $=$ Rs 70

Cost of $1378 / 7 \mathrm{~m}^{2}$ canvas $=$ Rs $1378 / 7$ * $70=$ Rs $1,37,280$

Thus the cost of canvas required to make the tent is Rs 1, 37, 280.