A cylindrical bucket, 28 cm in diameter and 72 cm and high, is full of water.

 Given: Diameter of the cylindrical bucket = 28 cm
i.e., radius = 14 cm
Height of the cylindrical bucket, h1 = 72 cm
Length of the rectangular tank, l = 66 cm
Breadth of the rectangular tank, b = 28 cm
Let the height of the rectangular tank be h cm.
The water from the cylindrical bucket is emptied into the rectangular tank.
i.e., volume of the bucket = volume of the tank

$\Rightarrow \pi r^{2} h_{1}=l \times b \times h$

$\Rightarrow \frac{22}{7} \times 14^{2} \times 72=66 \times 28 \times h$

$\Rightarrow h=\frac{22 \times 14 \times 2 \times 72}{66 \times 28}=24 \mathrm{~cm}$

∴ Height of the rectangular tank = 24 cm