**Question:**

A cylindrical container with diameter of base 56 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 32 cm × 22 cm × 14 cm. Find the rise in the level of the water when the solid is completely submerged.

**Solution:**

Diameter of the cylindrical container =* d* cm = 56 cm

Radius of the cylindrical container = *r* cm = 28 cm

Volume of cylindrical container = Volume of the rectangular solid

Length of the rectangular solid = 32 cm

Breadth of the rectangular solid = 22 cm

Height of the rectangular solid = 14 cm

Volume of the rectangular solid = Length x Breadth x Height = 32 cm x 22 cm x 14 cm = 9856 cm3

Volume of the cylindrical container = 9856 cm3 = πr2*h*

$9856 \mathrm{~cm}^{3}=\frac{22}{7}(28 \mathrm{~cm})^{2} h$

*h *= 4 cm

Thus, when the solid is completely submerged, the water will rise up to 4 cm.