Question:
A cylindrical tube, open at both ends, is made of metal. The internal diameter of the tube is 10.4 cm and its length is 25 cm. The thickness of the metal is 8 mm everywhere. Calculate the volume of the metal.
Solution:
Here, r = Inner radius = 5.2 cm
R = Outer radius
t = Thickness = 0.8 cm
h = Length = 25 cm
R = r + t = 5.2 cm + 0.8 cm = 6 cm
Volume of the metal = π h (R2 - r2)
$=\frac{22}{7}$$\times(25) \times\left((6)^{2}-(5.2)^{2}\right)$
= 704 cm3
Thus, the volume of the metal is 704 cm3.
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