A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Then, he found that each table was sold for the same price. Find the cost price of each table.
Los $s$ on the first table $=15 \%$
Therefore, $S . P=C . P\left(\frac{100-l \text { oss } \%}{100}\right)$
S. P $=\frac{85 x}{100}=$ Rs. $0.85 x$
Gain on the second table $=36 \%$
Therefore, S.P $=C . P\left(\frac{100+g \text { ain } \%}{100}\right)$
$S . P=$ Rs. $1.36(3120-x)$
Since both tables have the same S.P,
So, $0.85 \mathrm{x}=1.36(3120-x)$
$0.85 x=4243.20-1.36 x$
$2.21 x=4243.20$
$x=\frac{4243.20}{2.21}$
$x=$ Rs. 1920
So, the cost price of $t h e$ first table $i s$ Rs. 1920 .
Cost price of the second table $=$ Rs. $(3120-1920)=$ Rs. 1200
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