A drinking glass is in the shape of a frustum of a cone of height 14 cm.

R = 2 cm, r = 1 cm, h = 14 cm

Capacity of the glass = volume of the frustum with radii of ends as 2 cm and 1 cm and height 14 cm 

$=\frac{\mathbf{1}}{\mathbf{3}} \pi \mathrm{h}\left\{\mathrm{R}^{2}+\mathrm{r}^{2}+\mathrm{Rr}\right\}$

$=\frac{\mathbf{1}}{\mathbf{3}} \pi \times 14 \times\left\{(2)^{2}\right.$$\left.+(1)^{2}+2(1)\right\} \mathrm{cm}^{3}$

$=\frac{\mathbf{1}}{\mathbf{3}} \times \frac{\mathbf{2 2}}{\mathbf{7}} \times 14 \times 7 \mathrm{~cm}^{3}$

$=\frac{308}{3}=102 \frac{2}{3} \mathrm{~cm}^{3}$