 # A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm.

Question:

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?

Solution:

Given:

Base of a flooring tile that is in the shape of a parallelogram $=\mathrm{b}=24 \mathrm{~cm}$

Corresponding height $=\mathrm{h}=10 \mathrm{~cm}$

Now, in a parallelogram :

Area $(\mathrm{A})=$ Base $(\mathrm{b}) \times$ Height $(\mathrm{h})$

$\therefore$ Area of a tile $=24 \mathrm{~cm} \times 10 \mathrm{~cm}=240 \mathrm{~cm}^{2}$

Now, observe that the area of the floor is $1080 \mathrm{~m}^{2}$.

$1080 \mathrm{~m}^{2}=1080 \times 1 \mathrm{~m} \times 1 \mathrm{~m}$

$=1080 \times 100 \mathrm{~cm} \times 100 \mathrm{~cm}$          $($ Because $1 \mathrm{~m}=100 \mathrm{~cm})$

$=1080 \times 100 \times 100 \times \mathrm{cm} \times \mathrm{cm}$

$=10800000 \mathrm{~cm}^{2}$

$\therefore$ Number of required tiles $=\frac{10800000}{240}=45000$

Hence, we need 45000 tiles to cover the floor.