# A force F = a + bx acts on a particle in the x-direction,

Question:

A force $\mathrm{F}=\mathrm{a}+\mathrm{bx}$ acts on a particle in the x-direction, where a and $\mathrm{b}$ are constants. Find the work done by this force during a displacement from $x=0$ to $x=d$.

Solution: