A godown measures 40 m × 25 m × 15 m.
Question. A godown measures $40 \mathrm{~m} \times 25 \mathrm{~m} \times 15 \mathrm{~m}$. Find the maximum number of wooden crates each measuring $1.5 \mathrm{~m} \times 1.25 \mathrm{~m} \times 0.5 \mathrm{~m}$ that can be stored in the godown.


Solution:

The godown has its length $\left(l_{1}\right)$ as $40 \mathrm{~m}$, breadth $\left(b_{1}\right)$ as $25 \mathrm{~m}$, height $\left(h_{1}\right)$ as $15 \mathrm{~m}$, while the wooden crate has its length $\left(t_{2}\right)$ as $1.5 \mathrm{~m}$, breadth $\left(b_{2}\right)$ as $1.25 \mathrm{~m}$, and height $\left(h_{2}\right)$ as $0.5$ $\mathrm{m}$.

Therefore, volume of godown $=l_{1} \times b_{1} \times h_{1}$

$=(40 \times 25 \times 15) \mathrm{m}^{3}$

$=15000 \mathrm{~m}^{3}$

Volume of 1 wooden crate $=I_{2} \times b_{2} \times h_{2}$

$=(1.5 \times 1.25 \times 0.5) \mathrm{m}^{3}$

$=0.9375 \mathrm{~m}^{3}$

Let n wooden crates can be stored in the godown.

Therefore, volume of n wooden crates = Volume of godown

$0.9375 \times n=15000$

$\mathrm{n}=\frac{15000}{0.9375}=16000$

Therefore, 16,000 wooden crates can be stored in the godown.
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