Question.
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall
Solution:
Let AC = x metres be the distance of the foot of the ladder from the base of the wall.
AB = 8 m (Height of window)
BC = 10 m (length of ladder)
Now, $\quad x^{2}+(8)^{2}=(10)^{2}$
$\Rightarrow x^{2}=100-64=36 \Rightarrow x=6$, i.e., $A C=6 m$
Let AC = x metres be the distance of the foot of the ladder from the base of the wall.
AB = 8 m (Height of window)
BC = 10 m (length of ladder)
Now, $\quad x^{2}+(8)^{2}=(10)^{2}$
$\Rightarrow x^{2}=100-64=36 \Rightarrow x=6$, i.e., $A C=6 m$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.