A life insurance agent found the following data for distribution of ages of 100 policy holders.

Here, $\ell=35, \mathrm{n}=100, \mathrm{f}=33, \mathrm{cf}=45, \mathrm{~h}=5$

Median $=\ell+\left\{\frac{\frac{\mathbf{n}}{\mathbf{2}}-\mathbf{c f}}{\mathbf{f}}\right\} \times \mathrm{h}$

$=35+\left\{\frac{\mathbf{5 0}-\mathbf{4 5}}{\mathbf{3 3}}\right\} \times 5$

$=35+\frac{\mathbf{2 5}}{\mathbf{3 3}}$

= 35 + 0.76

= 35.76 years.