A line passes through the point

Question:

A line passes through the point $A(-2,4,-5)$ and is parallel to the line $\frac{x+3}{3}=\frac{y-4}{5}=\frac{z+8}{6}$. The vector equation of the line is

A. $\overrightarrow{\mathrm{r}}=(-3 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-8 \hat{\mathrm{k}})+\lambda(-2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-5 \hat{\mathrm{k}})$

B. $r=(-2 \hat{\imath}+4 \hat{\jmath}-5 \hat{k})+\lambda(3 \hat{\imath}+5 \hat{\jmath}+6 \hat{k})$

C.$\overrightarrow{\mathrm{r}}=(3 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}+6 \hat{\mathrm{k}})+\lambda(-2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-5 \hat{\mathrm{k}})$

D. none of these

Solution:

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now