A particle executes the motion described by

Question:

A particle executes the motion described by x(t) = x0 (1 – e-γt) where t ≥ 0, x0 > 0

(a) Where does the particles start and with what velocity?

(b) Find maximum and minimum values of x(t), v(t), a(t). Show that x(t) and a(t) increase with time and v(t) decreases with time.

Solution:

(a) x(t) = x0 (1 – e-γt)

v(t) = dx(t)/dt = +x0 γ e-γt

a(t) = dv/dt = x0 γ2 e-γt

v(0) = x0 γ

(b) x(t) is minimum at t = 0 since t = 0 and [x(t)]min = 0

x(t) is maximum at t = ∞ since t = ∞ and [x(t)]max = e-γt = ∞

v(t) is maximum at t = 0 since t = 0 and v(0) = x0γ

v(t) is minimum at t = ∞ since t = ∞ and v(∞) = 0

a(t) is maximum at t = ∞ since t = ∞ and a(∞) = 0

a(t) is minimum at t = 0 since t = 0 and a(0) = -x0 γ2

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now