A particle is moving with constant acceleration ' a'.

Question:

A particle is moving with constant acceleration ' $a$ '.

Following graph shows $v^{2}$ versus $x$ (displacement) plot. The acceleration of the particle is______ $\mathrm{m} / \mathrm{s}^{2} .$

Solution:

$y=m x+C$

$v^{2}=\frac{20}{10} x+20$

$v^{2}=2 x+20$

$2 v \frac{d v}{d x}=2$

$\therefore a=v \frac{d v}{d x}=1$

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