Question:
A particle is moving with constant acceleration ' $a$ '.
Following graph shows $v^{2}$ versus $x$ (displacement) plot. The acceleration of the particle is______ $\mathrm{m} / \mathrm{s}^{2} .$
Solution:
$y=m x+C$
$v^{2}=\frac{20}{10} x+20$
$v^{2}=2 x+20$
$2 v \frac{d v}{d x}=2$
$\therefore a=v \frac{d v}{d x}=1$
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