A particle of mass $m$ with an initial velocity $u \hat{i}$ collides perfectly elastically with a mass $3 \mathrm{~m}$ at rest. It moves with a velocity $v \hat{j}$ after collision, then, $v$ is given by:
Correct Option:
(3) From conservation of inear momentum
$m u \hat{i}+0=m v \hat{j}+3 m \overrightarrow{v^{\prime}}$
$\overrightarrow{v^{\prime}}=\frac{u}{3} \hat{i}-\frac{v}{3} \hat{j}$
From kinetic energy conservation,
$\frac{1}{2} m u^{2}=\frac{1}{2} m v^{2}+\frac{1}{2}(3 m)\left(\left(\frac{u}{3}\right)^{2}+\left(\frac{v}{3}\right)^{2}\right)$
or, $m u^{2}=m v^{2}+\frac{m u^{2}}{3}+\frac{m v^{2}}{3}$
$\therefore v=\frac{u}{\sqrt{2}}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.