Question:
A perfect square number having n digits, where n is even, will have square root with
(a) $(n+1)$ digit
(b) $\frac{n}{2}$ digit
(c) $\frac{n}{3}$ digit
(d) $\left(\frac{n+1}{2}\right)$ digit
Solution:
(b) A perfect square number having n digits, where n is even, will have square root with n/2 digit.
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